MTS 21 25-07-2022 Shift 1


Question 1

A car moves through 20m in 3 minutes and the next 50 km at a speed of 100 km/h. What is the approximate average speed of the car?

 


Options

A

B

C

D


Solution:

Correct Answer:

D


Average Speed  = Total DistanceTotal Time \frac{\text{Total Distance}}{\text{Total Time }}
First 20m in 3 minutes or 180 seconds

and next 50 km at speed of 100 km/h then time = 50100\frac{50}{100} hours = 12\frac12 hours = 1800 seconds
Average Speed = 20+500001800+180 \frac{20+50000}{1800+180} 
Average Speed  = 500201980\frac{50020}{1980} = 25.26 m/s

औसत  चाल = कुल  दूरीकुल समय\frac{\text{कुल  दूरी} }{\text{कुल समय}}
पहले 20 मीटर के लिए 3 मिनट या 180 सेकंड का समय लगता है 

तथा अगले 50 km के लिए चाल 100 km/h है तब लगा समय = 50100\frac{50}{100} hours = 12\frac12 hours = 1800 seconds
औसत  चाल  = 20+500001800+180\frac{20+50000}{1800+180}
औसत  चाल  = 500201980\frac{50020}{1980} = 25.26 m/s

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