MTS 21 25-07-2022 Shift 1


Question 1

The population of a town increases by 8% every year. If the present population of the town is 14,580, then what was the
population of the town 2 years ago?

एक कस्बे की जनसंख्या में प्रति वर्ष 8% की वृद्धि होती है। यदि कस्बे की वर्तमान जनसंख्या 14,580 है, तो 2 वर्ष
पूर्व कस्बे की जनसंख्या कितनी थी?


Options

A

B

C

D


Solution:

Correct Answer:

D


Present population of the town = 14580

Rate of increase per year = 8%

population 2 years ago = 14580 ×\times 100108\frac{100}{108} ×\times 100108\frac{100}{108} = 12500

क़स्बे की वर्तमान जनसंख्या  = 14580

प्रतिवर्ष जनसंख्या में वृधि की दर = 8%

2 वर्ष पहले जनसंख्या  = 14580 ×\times 100108\frac{100}{108} ×\times 100108\frac{100}{108} = 12500

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