MTS 21 25-07-2022 Shift 3


Question 1

A, B and C can do a piece of work in 10, 20 and 30 days, respectively. In how many days can A do the work if he is
assisted by B and C on every third day?

A, Bऔर C एक कार्य को क्रमशः 10, 20 और 30 दिनों में कर सकते हैं। यदि प्रत्येक तीसरे दिन B और C उसकी
मदद करते हैं, तो A इस कार्य को कितने दिनों में कर सकता है?


Options

A

B

C

D


Solution:

Correct Answer:

A


\begin{align}
\text{Lets Total work } = \text{L.C.M. of A,B and C}\\
\text{Total work} = 60\\
\text{Efficiency of A,B and C = 6, 3 and 2 }\\
\text{Work done by A in three days with the help of B and C on third day = 6 + 6 +  11 = 23}\\
\text{No. of Days}= 3+3+1+1+\frac{2}{11}=8\frac{2}{11}
\end{align}


माना कुल कार्य  = लघुतम समापवर्त्य A,B और  C का 
कुल कार्य  = 60
A,B और  C की क्षमता  = 6, 3 and 2 
A के द्वारा B तथा C की मदद से तीन दिनो में किया गया कार्य  = 6 + 6 +  11 = 23
दिनो की संख्या = 3+3+1+1+211\frac{2}{11}=8211\frac{2}{11}
 

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