MTS 21 25-07-2022 Shift 3


Question 1

The lengths of the diagonals of a rhombus are 48 cm and 20 cm. What is the perimeter of the rhombus?

एक समचतुर्भुज के विकर्णों की लंबाइयां 48 cm और 20 cm हैं। समचतुर्भुज की परिमाप कितना है?


Options

A

B

C

D


Solution:

Correct Answer:

A


Lets Side and diagonals of rhombus = a,d1 and d2

In rhombus we know d122{\frac{d_1}{2}}^2+d222{\frac{d_2}{2}}^2 = a2a^2

242{24}^2+102{10}^2=a2a^2

a = 26

Perimeter of Rhombus = 4a = 104

माना की समचतुर्भुज की भुजा तथा विकर्ण  = a,d1 and d2

हम समचतुर्भुज में जानते है की d122{\frac{d_1}{2}}^2+d222{\frac{d_2}{2}}^2 = a2a^2

242{24}^2+102{10}^2=a2a^2

a = 26

समचतुर्भुज का परिमाप  = 4a = 104

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