CGL 21 Tier 2 Maths


Question 1

What is the value of 991199\frac{11}{99} + 991399\frac{13}{99} + 991599\frac{15}{99} + ..... + 996799\frac{67}{99}?

991199\frac{11}{99} + 991399\frac{13}{99} + 991599\frac{15}{99} + ..... + 996799\frac{67}{99} का मान क्या है?


Options

A

9712033\frac{97120}{33}

9712033\frac{97120}{33}

B

9512033\frac{95120}{33}

9512033\frac{95120}{33}

C

9422033\frac{94220}{33}

9422033\frac{94220}{33}

D

9622033\frac{96220}{33}

9622033\frac{96220}{33}


Solution:

Correct Answer:

B

9512033\frac{95120}{33}

9512033\frac{95120}{33}


991199\frac{11}{99} + 991399\frac{13}{99} + 991599\frac{15}{99} + ..... + 996799\frac{67}{99}

an = a + (n - 1)d  and S= n2\frac{n}{2}(a+an)

67 = 11 + (n - 1)2

n = 1 + 28 = 29

(99 + 99 + 99 + ... 29 times) + (11+13+15+......+6799\frac{11 + 13 + 15 + ...... + 67}{99})

99 (1 + 1 + 1 + .... 29 times) + 292×(11+67)99\frac{\frac{29}{2} \times (11 + 67)}{99}

99 ×\times 29   + 292×7899\frac{\frac{29}{2} \times 78}{99}

2871 + 37733\frac{377}{33}

94743+37733\frac{94743 + 377}{33}

9512033\frac{95120}{33}

 

991199\frac{11}{99} + 991399\frac{13}{99} + 991599\frac{15}{99} + ..... + 996799\frac{67}{99}

an = a + (n - 1)d और  S= n2\frac{n}{2}(a+an)

67 = 11 + (n - 1)2

n = 1 + 28 = 29

(99 + 99 + 99 + ... 29 times) + (11+13+15+......+6799\frac{11 + 13 + 15 + ...... + 67}{99})

99 (1 + 1 + 1 + .... 29 times) + 292×(11+67)99\frac{\frac{29}{2} \times (11 + 67)}{99}

99 ×\times 29   + 292×7899\frac{\frac{29}{2} \times 78}{99}

2871 + 37733\frac{377}{33}

94743+37733\frac{94743 + 377}{33}

9512033\frac{95120}{33}

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