CGL 21 Tier 2 Maths


Question 1

Two line charts are given below. Line chart 1 shows the ratio of number of males to the number of females in two companies A and B for the 5 years. Line chart 2 shows the total number of males (both companies A and B) and total number of females (both companies A and B) for the 5 years.

What is the ratio of number of males of company B in Y1 to the total number of females of company A in Y3 and Y5?

नीचे दो लाइन चार्ट दिए गए हैं। लाइन चार्ट 1, 5 वर्षों के लिए दो कंपनियों A और B में पुरुषों की संख्या का महिलाओं की संख्या से अनुपात दर्शाता है। लाइन चार्ट 2, 5 वर्षों के लिए पुरुषों की कुल संख्या (कंपनियां A और B दोनों) और महिलाओं की कुल संख्या (कंपनियां A और B दोनों) को दर्शाता है।

Y1 में कंपनी B के पुरुषों की संख्या का Y3 और Y5 में कंपनी A की महिलाओं की कुल संख्या से अनुपात कितना है?


Options

A

119 : 218

119 : 218

B

117 : 218

117 : 218

C

129 : 215

129 : 215

D

117 : 215

117 : 215


Solution:

Correct Answer:

D

117 : 215

117 : 215


With the help of the line chart - 1 

In Y1 the ratio of the number of males to the number of females in company A = 1.1

MAFA\frac{M_A}{F_A} = 1110\frac{11}{10}11x10x\frac{11x}{10x}

In Y1 the ratio of the number of males to the number of females in company B = 0.9

MBFB\frac{M_B}{F_B} = 910\frac{9}{10}9y10y\frac{9y}{10y}

With the help of the line chart - 2

Total number of males in Y1 = Y1(MA + MB) = 11x + 9y = 21100

Total number of males in Y1 = Y1(FA + FB) = 10x + 10y = 20600

x + y = 2060 or 11x + 11y = 22660

2y = 22660 - 21100 = 1560 or y = 780

number of males of company B in Y1 = 9y  = 7020

Now we will follow the same process for the calculation of the total number of females of company A in Y3 and Y5

For total number of females of company A in Y3 :-

4a + 27b = 18025 and 5a + 20b = 16000

135a - 80a = 55a = 432000 - 360500 = 71500

5a = 6500

number of females of company A in Y3 = 5a = 6500

For total number of females of company A in Y5 :-

7p + 17q = 13550 and 5p + 20q = 11800

140p - 85p = 55p = 271000 - 200600 = 70400

5p = 6400

number of females of company A in Y5 = 5p = 6400

total number of females of company A in Y3 and Y5 = 6500 + 6400 = 12900

Now ratio 7020 : 12900 or 117 : 215

With the help of the line chart - 1 

In Y1 the ratio of the number of males to the number of females in company A = 1.1

MAFA\frac{M_A}{F_A} = 1110\frac{11}{10}11x10x\frac{11x}{10x}

In Y1 the ratio of the number of males to the number of females in company B = 0.9

MBFB\frac{M_B}{F_B} = 910\frac{9}{10}9y10y\frac{9y}{10y}

With the help of the line chart - 2

Total number of males in Y1 = Y1(MA + MB) = 11x + 9y = 21100

Total number of males in Y1 = Y1(FA + FB) = 10x + 10y = 20600

x + y = 2060 or 11x + 11y = 22660

2y = 22660 - 21100 = 1560 or y = 780

number of males of company B in Y1 = 9y  = 7020

Now we will follow the same process for the calculation of the total number of females of company A in Y3 and Y5

For total number of females of company A in Y3 :-

4a + 27b = 18025 and 5a + 20b = 16000

135a - 80a = 55a = 432000 - 360500 = 71500

5a = 6500

number of females of company A in Y3 = 5a = 6500

For total number of females of company A in Y5 :-

7p + 17q = 13550 and 5p + 20q = 11800

140p - 85p = 55p = 271000 - 200600 = 70400

5p = 6400

number of females of company A in Y5 = 5p = 6400

total number of females of company A in Y3 and Y5 = 6500 + 6400 = 12900

Now ratio 7020 : 12900 or 117 : 215

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