What is the value of $$\frac{\cos50^{\circ}}{\sin40^{\circ}}+\frac{3cosec 80^{\circ}}{\sec10^{\circ}}- 2\cos50^{\circ} cosec40^{\circ}°$$ ?
$$\frac{cos50°}{sin 40°} + \frac{ 3 cosec80°}{ sec10°} - 2cos50°.cosec40° $$ का मान क्या है?
5
5
3
3
4
4
2
2
Correct Answer:
2
2
$$\frac{cos50°}{sin 40°} + \frac{ 3 cosec80°}{ sec10°} - 2cos50°.cosec40°$$
cos50° = cos(90° - 50°) = sin40°
cosec80° = sec10°
cosec40° = sec50°
1 + 3 - 2 = 2
$$\frac{cos50°}{sin 40°} + \frac{ 3 cosec80°}{ sec10°} - 2cos50°.cosec40°$$
cos50° = cos(90° - 50°) = sin40°
cosec80° = sec10°
cosec40° = sec50°
1 + 3 - 2 = 2
