CGL 22 : 05/12/2022 Shift 3


Question 1


Select the correct algebraic expression.

सही बीजीय व्यंजक का चयन कीजिए।

Options

A

ab – a – b + 1 = (a – 1) (1 – b)

ab – a – b + 1 = (a – 1) (1 – b)

B

ab – a – b + 1 = (a – 1) (b – 1)

ab – a – b + 1 = (a – 1) (b – 1)

C

ab + a – b + 1 = (1 – a) (1 – b) (1 – a) (1 + b)

ab + a – b + 1 = (1 – a) (1 – b) (1 – a) (1 + b)

D

ab – a – b + 1 = (1 – a) (b – 1)

ab – a – b + 1 = (1 – a) (b – 1)


Solution:

Correct Answer:

B

ab – a – b + 1 = (a – 1) (b – 1)

ab – a – b + 1 = (a – 1) (b – 1)


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